I cannot figure out the logic for how browserify bundles its required files. If I do this

require('./one/one.js');
require('./two/two.js');
require('./three/three.js');

The output is this

(function e(t,n,r){function s(o,u){if(!n[o]){if(!t[o]){var a=typeof require=="function"&&require;if(!u&&a)return a(o,!0);if(i)return i(o,!0);throw new Error("Cannot find module '"+o+"'")}var f=n[o]={exports:{}};t[o][0].call(f.exports,function(e){var n=t[o][1][e];return s(n?n:e)},f,f.exports,e,t,n,r)}return n[o].exports}var i=typeof require=="function"&&require;for(var o=0;o<r.length;o++)s(r[o]);return s})({1:[function(require,module,exports){
var app = "app";

console.log(one);
},{}],2:[function(require,module,exports){
require('./one/one.js');
require('./two/two.js');
require('./three/three.js');
//require('./three/three_a/three_a.js');
require('./app.js');
},{"./app.js":1,"./one/one.js":3,"./three/three.js":4,"./two/two.js":5}],3:[function(require,module,exports){
var one = "one";
},{}],4:[function(require,module,exports){
var three = "three";
},{}],5:[function(require,module,exports){
var two = "two";
},{}]},{},[2])

As you can see, 'three' is bundle before 'two' but thats not the order I required them in?

I cannot figure out the logic for how browserify bundles its required files. If I do this

require('./one/one.js');
require('./two/two.js');
require('./three/three.js');

The output is this

(function e(t,n,r){function s(o,u){if(!n[o]){if(!t[o]){var a=typeof require=="function"&&require;if(!u&&a)return a(o,!0);if(i)return i(o,!0);throw new Error("Cannot find module '"+o+"'")}var f=n[o]={exports:{}};t[o][0].call(f.exports,function(e){var n=t[o][1][e];return s(n?n:e)},f,f.exports,e,t,n,r)}return n[o].exports}var i=typeof require=="function"&&require;for(var o=0;o<r.length;o++)s(r[o]);return s})({1:[function(require,module,exports){
var app = "app";

console.log(one);
},{}],2:[function(require,module,exports){
require('./one/one.js');
require('./two/two.js');
require('./three/three.js');
//require('./three/three_a/three_a.js');
require('./app.js');
},{"./app.js":1,"./one/one.js":3,"./three/three.js":4,"./two/two.js":5}],3:[function(require,module,exports){
var one = "one";
},{}],4:[function(require,module,exports){
var three = "three";
},{}],5:[function(require,module,exports){
var two = "two";
},{}]},{},[2])

As you can see, 'three' is bundle before 'two' but thats not the order I required them in?

• javascript
• browserify

1 Answer 1

Looks like it’s alphabetical. Maybe Browserify sorts them that way or that’s just how it es from the OS. It doesn’t really make any difference—those are just the module definitions. Your code, inside those (require, module, exports) functions, will always run the same no matter what order the modules were defined in.

Here’s a simplified version of what Browserify is doing that may be more clear:

var modules = {
  './app.js': function (require, module, exports) {
    require('./one/one.js');
    require('./two/two.js');
    require('./three/three.js');
  },
  './two/two.js': function (require, module, exports) {
    console.log('two');
  },
  './one/one.js': function (require, module, exports) {
    console.log('one');
  },
  './three/three.js': function (require, module, exports) {
    console.log('three');
  }
};

function require (path) {
  var module = {exports: {}};
  modules[path](require, module, module.exports);
  return module.exports;
}

require('./app.js');

Even if you change the order the modules are defined you should always see the same output:

one
two
three