I want to write backtick inside backtick. (es6)

How do you create backtick in backtick ?

const apple = 'apple';
const grape = 'grape';
const money1 = 2000;
const money2 = 1000;


// before
console.log(`${apple} = ${grape === 'grape' ? '(' + money1 + ')' : '(' + money2 + ')'`;

// after  <-- I want
console.log(`${apple} = ${grape === 'grape' ? \`(${money1})\` : \`(${money2})\`}`;

I want to write backtick inside backtick. (es6)

How do you create backtick in backtick ?

const apple = 'apple';
const grape = 'grape';
const money1 = 2000;
const money2 = 1000;


// before
console.log(`${apple} = ${grape === 'grape' ? '(' + money1 + ')' : '(' + money2 + ')'`;

// after  <-- I want
console.log(`${apple} = ${grape === 'grape' ? \`(${money1})\` : \`(${money2})\`}`;

• javascript
• string
• ecmascript-6

• Your question isn't very clear. What do you want the actual log message to look like? – Barmar Commented Jun 13, 2019 at 0:42

3 Answers 3

Remove the backslashes:

const apple = 'apple';
const grape = 'grape';
const money1 = 2000;
const money2 = 1000;

console.log(`${apple} = ${grape === 'grape' ? `(${money1})` : `(${money2})`}`);

If you were asking about printing a literal backpack in a template string, then just use a backslash normally.

console.log(`\``);

To answer your question literaly: "to put a backtick in backticks" sounds like how to put a literal backtick into a string. To do that, escape it.

Escape it with a backslash. See https://developer.mozilla/en-US/docs/Web/JavaScript/Reference/Template_literals#Description

`\``

console.log(`\``)

But what you actually are trying to do is not so plex. The JavaScript syntax allows for nesting backticks within ${} without escaping them.

console.log(`Hello ${`world`}, ${`nesting ${`works too`}`}`);

I realize that your example is partially hypothetical, but there's a much simpler approach to your example that avoids the need for nested template literals:

const apple = 'apple';
const grape = 'grape';
const money1 = 2000;
const money2 = 1000;


console.log(`${apple} = (${grape === 'grape' ? money1 : money2})`);