This question is very similar to How do I find the Client ID of control within an ASP.NET GridView?
However I'm using a listview and a label:
<ItemTemplate>
<asp:ImageButton ImageUrl="Resources/info.png" ToolTip="info" OnClientClick="toggle('<%#((label)Container).FindControl( "PresetUploadDescription").ClientID %>');" ID="Description" runat="server"/>
<asp:Label ID="UploadDescription" BorderStyle="Solid" BorderColor="Goldenrod" BorderWidth="1" runat="server" Width="40em" CssClass="sc-Upload-description" Text='<%# Eval("Description") %>'></asp:Label>
....
I'm getting a "The server tag is not well formed" at the findcontrol() function...Any ideas why? I've tried both 'label' and 'control' casts...
This question is very similar to How do I find the Client ID of control within an ASP.NET GridView?
However I'm using a listview and a label:
<ItemTemplate>
<asp:ImageButton ImageUrl="Resources/info.png" ToolTip="info" OnClientClick="toggle('<%#((label)Container).FindControl( "PresetUploadDescription").ClientID %>');" ID="Description" runat="server"/>
<asp:Label ID="UploadDescription" BorderStyle="Solid" BorderColor="Goldenrod" BorderWidth="1" runat="server" Width="40em" CssClass="sc-Upload-description" Text='<%# Eval("Description") %>'></asp:Label>
....
I'm getting a "The server tag is not well formed" at the findcontrol() function...Any ideas why? I've tried both 'label' and 'control' casts...
Share Improve this question edited May 23, 2017 at 12:33 CommunityBot 11 silver badge asked Jan 18, 2012 at 23:27 GioGio 4,2293 gold badges32 silver badges33 bronze badges 4- maybe so but it didn't help... – Gio Commented Jan 18, 2012 at 23:34
- Try #<%=Control.ClientID%> and the error defines that if you dont give any spaces between each property it gives you that error. – coder Commented Jan 18, 2012 at 23:40
- Are you sure that syntax is correct? I tried <%# control.clientID %> and that got rid of the 'badly formed..' message but now all I have is the actual <#control.clientid # which doesn't work. – Gio Commented Jan 18, 2012 at 23:51
- I'm not using events i'm using javascript tied to onclick – Gio Commented Jan 19, 2012 at 0:00
1 Answer
Reset to default 3As far as I can tell, there are two ways to acplish what you are looking to do. Either use an asp:ImageButton server control and wire up the onclick client event using the OnItemDataBound event, or simply use an <input type="image" /> control and wire up the ClientID inline. The following example shows both approaches:
<%@ Page Language="C#" AutoEventWireup="true" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3/1999/xhtml">
<head runat="server"><title>OnClick Test</title></head>
<body>
<form id="form1" runat="server">
<div>
<asp:ListView ID="lv1" OnItemDataBound="lv1_ItemDataBound" runat="server">
<ItemTemplate>
<asp:Label ID="label1" Text="<%# Container.DataItem %>" runat="server" />
<asp:ImageButton ID="btn1"
ImageUrl="myimage.jpg"
AlternateText="Show Text"
runat="server" />
<input type="image" src="myimage.jpg" alt="Show Text"
onclick="alert(document.getElementById('<%# Container.FindControl("label1").ClientID %>').innerText);"
/>
<br />
</ItemTemplate>
</asp:ListView>
</div>
</form>
</body>
</html>
<script runat="server">
public void Page_Load(object sender, EventArgs e)
{
if (Page.IsPostBack) return;
lv1.DataSource = new[] {"Manny", "Moe", "Jack"};
lv1.DataBind();
}
protected void lv1_ItemDataBound(object sender, ListViewItemEventArgs e)
{
var label1 = e.Item.FindControl("label1") as Label;
var btn1 = e.Item.FindControl("btn1") as ImageButton;
if (label1 == null || btn1 == null) return;
btn1.Attributes.Add("onclick", "alert(document.getElementById('" + label1.ClientID + "').innerText);");
}
</script>