I'm trying to do a mouseover for the jquery and when the mouse is hovered over a certain row I can get the id from that row and populate information and display an image. However, I have been having the hardest time trying to do so.
Here is what I want to happen
Just like in the onSelectRow where I obtain the data using the following code
var ret = $('#list').jqGrid('getRowData', Id);
I want to use when I do a mouseover. However, I don't see a way of doing this. I tried the following under gridComplete
gridComplete: function() {'.jqgrow').mouseover(function(e) {
var rowId = $('.jqgrow').parent(tr:first).attr('id');
alert("You rolled over " + rowId.Id);
});
}
but it only gave me the ide number of the row of that table inside the jqgrid and I need the data from that row instead.
For instance, in my data I have Id, FirstName, LastName, FullName, Title, SortID
I would like to present a picture on the right side of my HTML page when hovered over certain rows by passing the Id to the HTML page, and querying through an array. If I can some how get the actual Id that's within my dataset I can do the rest.
Any help would be lovely.
I have given the entire code of my jqGrid at the bottom for reference.
jQuery("#list").jqGrid({
url: '/Providers/DynamicGridData/',
datatype: 'json',
mtype: 'GET',
colNames: ['Id', 'LastName', 'FirstName', 'FullName', 'Title', 'Url', 'SortId'],
colModel: [
{ name: 'Id', index: 'Id', width: 30, align: 'left', hidden: true },
{ name: 'LastName', index: 'LastName', width: 30, align: 'left', hidden: true },
{ name: 'FirstName', index: 'FirstName', width: 30, align: 'left', hidden: true },
{ name: 'FullName', index: 'FullName', width: 100, align: 'left' },
/*{ name: 'FirstName', index: 'FirstName', width: 100, align: 'left' },*/
{name: 'Title', index: 'Title', width: 200, align: 'left' },
{ name: 'Url', index: 'Url', width: 30, align: 'left', hidden: true },
{ name: 'SortId', index: 'SortId', width: 30, align: 'left', hidden: true}],
pager: jQuery('#pager'),
rowNum: 10,
rowList: [5, 10, 20, 50],
sortname: 'Id',
scrollOffset: 0,
width: '425',
altRows: 'true',
altClass: 'ui-priority-secondary',
autowidth: 'true',
height: '300',
altRows: 'true',
altClass: 'ui-priority-secondary',
viewrecords: true,
caption: 'Clinical Providers',
onSelectRow: function() {
var Id = $("#list").jqGrid('getGridParam', 'selrow');
if (Id) {
var ret = $('#list').jqGrid('getRowData', Id);
var url = ret.Url;
url.split(' ').join('');
//alert("id=" + ret.Id + "FullName=" + ret.FullName + "...");
window.location = "/" + url;
}
else { alert("Please select a row"); }
},
gridComplete: function() {
$('.jqgrow').mouseover(function(e) {
var rowId = $('.jqgrow').
alert("You rolled over " + rowId.Id);
});
}
});
I'm trying to do a mouseover for the jquery and when the mouse is hovered over a certain row I can get the id from that row and populate information and display an image. However, I have been having the hardest time trying to do so.
Here is what I want to happen
Just like in the onSelectRow where I obtain the data using the following code
var ret = $('#list').jqGrid('getRowData', Id);
I want to use when I do a mouseover. However, I don't see a way of doing this. I tried the following under gridComplete
gridComplete: function() {'.jqgrow').mouseover(function(e) {
var rowId = $('.jqgrow').parent(tr:first).attr('id');
alert("You rolled over " + rowId.Id);
});
}
but it only gave me the ide number of the row of that table inside the jqgrid and I need the data from that row instead.
For instance, in my data I have Id, FirstName, LastName, FullName, Title, SortID
I would like to present a picture on the right side of my HTML page when hovered over certain rows by passing the Id to the HTML page, and querying through an array. If I can some how get the actual Id that's within my dataset I can do the rest.
Any help would be lovely.
I have given the entire code of my jqGrid at the bottom for reference.
jQuery("#list").jqGrid({
url: '/Providers/DynamicGridData/',
datatype: 'json',
mtype: 'GET',
colNames: ['Id', 'LastName', 'FirstName', 'FullName', 'Title', 'Url', 'SortId'],
colModel: [
{ name: 'Id', index: 'Id', width: 30, align: 'left', hidden: true },
{ name: 'LastName', index: 'LastName', width: 30, align: 'left', hidden: true },
{ name: 'FirstName', index: 'FirstName', width: 30, align: 'left', hidden: true },
{ name: 'FullName', index: 'FullName', width: 100, align: 'left' },
/*{ name: 'FirstName', index: 'FirstName', width: 100, align: 'left' },*/
{name: 'Title', index: 'Title', width: 200, align: 'left' },
{ name: 'Url', index: 'Url', width: 30, align: 'left', hidden: true },
{ name: 'SortId', index: 'SortId', width: 30, align: 'left', hidden: true}],
pager: jQuery('#pager'),
rowNum: 10,
rowList: [5, 10, 20, 50],
sortname: 'Id',
scrollOffset: 0,
width: '425',
altRows: 'true',
altClass: 'ui-priority-secondary',
autowidth: 'true',
height: '300',
altRows: 'true',
altClass: 'ui-priority-secondary',
viewrecords: true,
caption: 'Clinical Providers',
onSelectRow: function() {
var Id = $("#list").jqGrid('getGridParam', 'selrow');
if (Id) {
var ret = $('#list').jqGrid('getRowData', Id);
var url = ret.Url;
url.split(' ').join('');
//alert("id=" + ret.Id + "FullName=" + ret.FullName + "...");
window.location = "/" + url;
}
else { alert("Please select a row"); }
},
gridComplete: function() {
$('.jqgrow').mouseover(function(e) {
var rowId = $('.jqgrow').
alert("You rolled over " + rowId.Id);
});
}
});
3 Answers
Reset to default 3I'm trying this code and it works fine:
gridComplete: function() {
$('.jqgrow').mouseover(function(e) {
var rowId = $(this).attr('id');
alert('You rolled over ' + rowId);
});
}
I am confused - when you say:
var rowId = $('.jqgrow').parent(tr:first).attr('id');
That should be returning the ID of the row. You can then pass rowID to the getRowData method to retrieve additional data for the row.
try this code..this code work... this code retrieve jqgrid row object ..
$('.jqgrow').mouseover(function(e) {
var rowId = $(this).attr('id');
var dataFromTheRow = jQuery("#list").jqGrid('getRowData',rowId);// this is your jqgrid row object;
alert('your jqgrid row object id = ' + dataFromTheRow.id);
});