categories - Show child taxonomies (that have posts) of the current parent taxonomy|Programmer puzzle solving

For the life of me I can't see why this isn't working. It works fine like this (normal categories)

<?php
if (is_category())
{
    $cur_cat = get_query_var('cat');
    if ($cur_cat) 
    {
        $new_cats = wp_list_categories('show_option_none=&echo=false&child_of=' . $cur_cat . '&depth=1&title_li=&show_count=1&hide_empty=1');
        echo '' . $new_cats . '';
    }
}
?>

But it doesn't work like this with a custom taxonomy...

<?php
if (is_taxonomy())
{
    $cur_catp = get_query_var('catp');
    if ($cur_catp) 
    {
        $new_catsp = wp_list_categories('show_option_none=&echo=false&child_of=' . $cur_catp . '&depth=1&title_li=&show_count=1&hide_empty=1&taxonomy=p_scales');
        echo '' . $new_catsp . '';
    }
}
?>

I need both to work side by side hence why I've changed the variables.

For the life of me I can't see why this isn't working. It works fine like this (normal categories)

<?php
if (is_category())
{
    $cur_cat = get_query_var('cat');
    if ($cur_cat) 
    {
        $new_cats = wp_list_categories('show_option_none=&echo=false&child_of=' . $cur_cat . '&depth=1&title_li=&show_count=1&hide_empty=1');
        echo '' . $new_cats . '';
    }
}
?>

But it doesn't work like this with a custom taxonomy...

<?php
if (is_taxonomy())
{
    $cur_catp = get_query_var('catp');
    if ($cur_catp) 
    {
        $new_catsp = wp_list_categories('show_option_none=&echo=false&child_of=' . $cur_catp . '&depth=1&title_li=&show_count=1&hide_empty=1&taxonomy=p_scales');
        echo '' . $new_catsp . '';
    }
}
?>

I need both to work side by side hence why I've changed the variables.

Share Improve this question edited Jan 27, 2019 at 11:58 asked Nov 26, 2018 at 10:58 Pete 1,0582 gold badges14 silver badges40 bronze badges

You should use is_tax('p_scales') and not is_taxonomy().. – Sally CJ Commented Nov 26, 2018 at 13:13
That doesn't work – Pete Commented Nov 26, 2018 at 15:10
Are you sure the taxonomy p_scales is valid? And that the WordPress query var catp exists for the requested URL? Try var_dump( $cur_catp ) and see if it's a proper ID of a valid term. – Sally CJ Commented Nov 27, 2018 at 14:45
p_scales is definitely the custom taxonomy slug. I don't know what you mean by the query var catp? – Pete Commented Nov 27, 2018 at 15:15
1 Well, you got this code: $cur_catp = get_query_var('catp'); in the question.. And did you try the var_dump() right after that code? – Sally CJ Commented Nov 27, 2018 at 15:24

| Show 2 more comments

1 Answer 1

Sorted by: Reset to default 1

Props to Sally for improving on this to show post count

$term = get_queried_object();

$children = get_terms( $term->taxonomy, array(
    'parent'    => $term->term_id,
    'hide_empty' => false
) );

if ( $children ) { 
    foreach( $children as $subcat )
    {
        echo '<li><a href="' . esc_url(get_term_link($subcat, $subcat->taxonomy)) . '">' . // wrapped
          $subcat->name . ' (' . $subcat->count . ')' . '</a></li>';
    }
}

UPDATE

To show the posts count:

As pointed in the comment, and based on the above code, you can use $subcat->count to display the number of posts in the specific term.

Therefore I replaced the $subcat->name . '</a></li>' with:

$subcat->name . ' (' . $subcat->count . ')' . '</a></li>'

which outputs something like: Term Name (1), Another Term Name (0), etc.

For the original code in question (using wp_list_categories()), here's how to fix it, and the fixed code:

Replace the is_category() with is_tax( 'p_scales' ).

Replace the get_query_var( 'cat' ) with get_queried_object_id().

if (is_tax('p_scales'))
{
    $cur_cat = get_queried_object_id();
    if ($cur_cat)
    {
        $new_cats = wp_list_categories('show_option_none=&echo=false&child_of=' . // wrapped
          $cur_cat . '&depth=1&title_li=&show_count=1&hide_empty=1&taxonomy=p_scales');
        echo '' . $new_cats . '';
    }
}

Programmer puzzle solving

categories - Show child taxonomies (that have posts) of the current parent taxonomy

1 Answer 1

UPDATE

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